This section gives a worked example of computing the volume of a rectangular prism.
The relevant unit conversions for length are
and, for capacity,
The conversion between capacity units and volume units is given by
See Vol. I §1 (Units of length), Vol. I §3 (Units of capacity), and Vol. II §10 Extended commentary.
Chinese source text: Version A, Version B, Version C, Version D.
Unless noted otherwise, I follow the text from Version D, 《知不足齋叢書》本.
Source text | Target text | Notes |
---|---|---|
今有方窖、廣四丈六尺、長五丈四尺、深三丈五尺。問受粟幾何。 | Suppose there be [a] rectangular cellar, of breadth four rods [and] six rules, length five rods [and] four rules, [and] depth three rods [and] five rules. [We] ask, how much grain beareth [it]? | |
答曰、五萬三千六百六十六斛六斗六升三分升之二。 | Answer saith: five myriad three thousand six hundred [and] sixty-six barrels, six pecks, six quarts, [and] two thirds of [a] quart. | |
術曰、置廣四丈六尺、長五丈四尺、相乘、得二千四百八十四尺。 | Method saith: put [down the] breadth four rods [and] six rules, [and the] length five rods [and] four rules, [which], multiplied with each other, result in two thousand four hundred [and] eighty-four rules. | |
以深三丈五尺乘之、得八萬六千九百四十尺。 | Multiplying it by [the] depth three rods [and] five rules, resulteth in eight myriad six thousand nine hundred [and] forty rules. | |
以斛法一尺六寸二分除之、即得。 | Dividing it by [the] barrel divisor, one rule, six inches, [and] two tenths, [we] are done. |
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Conway (2023). "Sun Tzŭ's Computational Classic: Volume II §11". <https://yawnoc.github.io/sun-tzu/ii/11> Accessed yyyy-mm-dd.